Calculate the mass of the sediment obtained by the interaction of calcium chloride weighing 22.2 g with sodium carbonate.

1. Let’s make the equation:
CaCl2 + Na2CO3 = CaCO3 + 2NaCl – obtained calcium carbonate in the sediment;
2. Let’s calculate the molecular weights of substances:
M (CaCl2) = 40 + 35.5 * 2 = 111 g / mol;
M (CaCO3) = 40 + 12 +16 * 3 = 100 g / mol;
3. Determine the amount of moles of calcium carbonate:
Y (CaCl2) = m / M = 22.2 / 111 = 0.2 mol;
4. Let us write down the equations based on the data:
0.2 mol (CaCl2) – X mol (CaCO3);
-1 mol -1 mol hence, X mol (CaCO3) = 0.2 * 1/1 = 0.2 mol;
5. Let’s calculate the mass:
m (CaCO3) = Y * M = 0.2 * 100 = 20 g.
Answer: in this reaction, a calcium carbonate salt with a mass of 20 g was released.