# Calculate the mass of the sediment resulting from the interaction of 200 g of a 10%

**Calculate the mass of the sediment resulting from the interaction of 200 g of a 10% solution of magnesium sulfate with an excess of sodium carbonate**

The reaction between magnesium sulfate and sodium carbonate is described by the following chemical reaction equation:

MgSO4 + Na2CO3 = MgCO3 + Na2SO4;

From 1 mole of magnesium sulfate, 1 mole of magnesium carbonate is synthesized. This reaction requires 1 mole of sodium carbonate.

Let’s calculate the chemical amount of a substance contained in 200 grams of a 10% solution of magnesium sulfate.

M MgSO4 = 24 + 32 + 16 x 4 = 120 grams / mol;

N MgSO4 = 200 x 0.1 / 120 = 0.167 mol;

During the reaction, the same amount of magnesium carbonate will be synthesized.

Let’s calculate the weight of magnesium carbonate. To do this, we multiply the amount of the substance by its molar weight.

M MgCO3 = 24 + 12 + 16 x 3 = 84 grams / mol;

M MgCO3 = 0.167 x 84 = 14.028 grams;