Calculate the mass of the sediment that forms when mixing a 200 g solution of argentum nitrate with a mass

Calculate the mass of the sediment that forms when mixing a 200 g solution of argentum nitrate with a mass fraction of salt 17% and a sodium phosphate solution weighing 200 g with a mass fraction of salt 8.2%

Given:
m solution (AgNO3) = 200 g
ω (AgNO3) = 17%
m solution (Na3PO4) = 200 g
ω (Na3PO4) = 8.2%

Find:
m (draft) -?

1) 3AgNO3 + Na3PO4 => Ag3PO4 ↓ + 3NaNO3;
2) m (AgNO3) = ω * m / 100% = 17% * 200/100% = 34 g;
3) n (AgNO3) = m / M = 34/170 = 0.2 mol;
4) m (Na3PO4) = ω * m / 100% = 8.2% * 200/100% = 16.4 g;
5) n (Na3PO4) = m / M = 16.4 / 164 = 0.1 mol;
6) n (Ag3PO4) = n (AgNO3) / 3 = 0.2 / 3 = 0.07 mol;
7) m (Ag3PO4) = n * M = 0.07 * 419 = 29.3 g.

Answer: The mass of Ag3PO4 is 29.3 g.