Calculate the mass of the sediment which is formed by 305 g of sodium silicate with a yield of 98%.
July 26, 2021
Let’s implement the solution:
1. Let us write down the equation according to the problem statement:
Na2SiO3 + 2HCl = H2SiO3 + 2NaCl – ion exchange reaction, obtained silicic acid in the precipitate;
2. Calculations by formulas:
M (Na2SiO3) = 121.8 g / mol;
M (H2SiO3) = 78 g / mol.
3. Determine the number of moles of sodium silicate, if the mass is known:
Y (Na2SiO3) = m / M = 305 / 121.8 = 2.5 mol;
Y (H2SiO3) = 2.5 mol since the amount of these substances according to the equation is equal to 1 mol.
4. Find the theoretical mass for the product:
m (theoretical) = Y * M = 2.5 * 78 = 195 g;
W = m (practical) / m (theoretical) * 100;
m (practical) H2SiO3 = 0.98 * 195 = 191.1 g.
Answer: during the reaction, silicic acid with a mass of 191.1 g was obtained.
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