Calculate the mass of the sediment, which is formed by the interaction of 20 g

Calculate the mass of the sediment, which is formed by the interaction of 20 g of potassium hydroxide and 200 g of a 10% solution of ferrous sulfate (2)

Given:
m (KOH) = 20 g
m solution (FeSO4) = 200 g
ω (FeSO4) = 10%

To find:
m (draft) -?

1) 2KOH + FeSO4 => Fe (OH) 2 ↓ + K2SO4;
2) n (KOH) = m / M = 20/56 = 0.4 mol;
3) m (FeSO4) = ω * m solution / 100% = 10% * 200/100% = 20 g;
4) n (FeSO4) = m / M = 20/152 = 0.1 mol;
5) n (Fe (OH) 2) = n (FeSO4) = 0.1 mol;
6) m (Fe (OH) 2) = n * M = 0.1 * 90 = 9 g.

Answer: The mass of Fe (OH) 2 is 9 g.