2 pedestrians left points A and B at the same time towards each other. They met 40 minutes after their departure

2 pedestrians left points A and B at the same time towards each other. They met 40 minutes after their departure, and 32 minutes after the meeting, the first came to B. How many hours after leaving B, the second came to A?

1. The distance between points A and B is equal to: S km;

2. Before the meeting, the first pedestrian has passed: S1 km;

3. The second pedestrian traveled: S2 km;

4. The meeting time for pedestrians is equal to: Tb = 40 min;

5. Speed ​​of the first pedestrian: V1 km / h;

6. Speed ​​of the second pedestrian: V2 km / h;

7. After the meeting, the first pedestrian arrived at point B in: T1 = 32 minutes;

8. The second pedestrian came to point A after the meeting in: T2 min;

9.Let’s define the ratio: S1 / S2 =

(V1 * Tb) / (V1 * T1) = (V2 * T2) / (V2 * Tb);

Tb / T1 = T2 / Tb;

10. Let’s calculate: T2 = Tb² / T1 = 40² / 32 = 1600/32 = 50 min;

11. The total travel time of the second pedestrian: To = Tb + T2 =

40 + 50 = 90 minutes = 1.5 hours.

Answer: the second pedestrian spent 1.5 hours on the whole journey.