Calculate the mass of the substance obtained by hydration of 44.8 liters of ethylene, if the product yield is 100%.

univerkov | March 4, 2021 | education

C2H4 + H2O = C2H5OH

Let’s find the amount of ethylene substance:

n (C2H4) = V (C2H4) / VM (C2H4) = 44.8 / 22.4 = 2 mol;

According to the stoichiometry of the reaction:

n (C2H5OH) = n (C2H4) = 2 mol;

Knowing the amount of ethanol substance, we find its mass:

m (C2H5OH) = n (C2H5OH) * M (C2H5OH) = 2 * 46 = 92 g.

Answer: m (C2H5OH) = 92 g.

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