Calculate the mass of the sulfuric acid solution (mass fraction of acid 9.8%), which must be taken for the reaction

Calculate the mass of the sulfuric acid solution (mass fraction of acid 9.8%), which must be taken for the reaction with the barium chloride solution to obtain 233 g of barium sulfate.

Barium chloride reacts with sulfuric acid. This forms a water-insoluble barium sulfate salt that precipitates. The reaction is described by the following chemical reaction equation.
BaCl2 + H2SO4 = BaSO4 + 2HCl;
Barium chloride reacts with sulfuric acid in equal molar amounts. In this case, the same amount of insoluble salt is synthesized.
Find the chemical amount of barium sulfate.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; N BaSO4 = 233/233 = 1 mol;
Let’s calculate the weight of this amount of sulfuric acid.
M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; m H2SO4 = 1 x 98 = 98 grams;