Calculate the mass of tribromaniline, which is formed by the reaction of aniline weighing 6.51 g with bromine water weighing 960 g

| November 16, 2020 | education

Calculate the mass of tribromaniline, which is formed by the reaction of aniline weighing 6.51 g with bromine water weighing 960 g, the mass fraction of bromine in which is 4%.

m – mass of matter
v – amount of substance
Mr – molecular weight
To find v, you must use the formula v = m / Mr.
Mr (aniline) = 93 g / mol.
v (aniline) = 6.51 / 93 = 0.07 mol.
m (bromine) = 960 * 0.04 = 38.4 g (0.04 is 4% bromine in the entire volume of bromine water).
Mr (bromine) = 160 g / mol.
v (bromine) = 38.4 / 160 = 0.24 mol.
The number of moles shows that bromine is taken in excess, which means that we calculate the mass of the final product based on aniline.
Mr (tribromaniline) = 330 g / mol.
m (tribromaniline) = 0.07 * 330 = 23.1 g.
Answer: the mass of tribromaniline is 23.1 g.



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