Calculate the mass of water formed by the interaction of 18 g of magnesium hydroxide

Calculate the mass of water formed by the interaction of 18 g of magnesium hydroxide with a solution of hydrochloric acid containing 18 g of hydrogen chloride.

m (Mg (OH) 2) = 18g
m (HCl) = 18g
Calculate:
m (H2O) -?
M (Mg (OH) 2) = 24.3 + 17 * 2 = 58.3 g / mol
M (HCl) = 1 + 35.45 = 36.45 g / mol
M (H2O) = 18g / mol
v (Mg (OH) 2) = 18g / 58.3g / mol = 0.31mol
v (HCl) = 18g / 36.45g / mol = 0.49mol
It can be seen from the reaction equation that Mg (OH) 2 interacts with HCl in a 1: 2 ratio. This means that (Mg (OH) 2) is taken in excess. We will solve the problem using (HCl).
It can be seen from the reaction equation that v (HCl) = v (H2O)
v (H2O) = 0.49 mol
m (H2O) = 0.49 mol * 18g / mol = 8.82g