Calculate the mass of water formed by the interaction of 200 g of 30% Naoh solution with sulfuric acid.

univerkov | March 5, 2021 | education

We compose the reaction equation and arrange the coefficients in it:
2NaOH + H2SO4 = Na2SO4 + 2H2O.
1) Find the mass of the sodium hydroxide solute. To do this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 200 * 30/100 = 60g.
2) Molar mass of sodium hydroxide: 23 + 1 + 16 = 40.
3) Amount of sodium hydroxide substance: 60/40 = 1.5 mol.
According to the reaction equation, there are two moles of water for two moles of hydroxide. This means that the amount of water substance is 1.5 mol.
4) Molar mass of water: 2 * 1 + 16 = 18.
5) Mass of water: 18 * 1.5 = 27g – the answer.

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