Calculate the mass of water formed if 4 g of methane is burned in sufficient oxygen.

univerkov | December 9, 2020 | education

CH4 + 2O2 = CO2 + 2H2O
n (CH4) = m (CH4) / M (CH4)
M (CH4) = 12 + 4 = 16 (g / mol)
n (CH4) = 4/16 = 0.25 (mol)
n (H2O) = 2n (CH4) = 2 * 0.25 = 0.5 (mol)
m (H2O) = M (H2O) * n (H2O)
M (H2O) = 2 + 16 = 18 (g / mol)
m (H20) = 18 * 0.5 = 9 (g)

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