Calculate the mass of water obtained by combustion in oxygen of hydrogen with an amount of 0.6 mol.

2 H2 + O2 = 2 H2O.

According to the reaction equation, from 2 mol of hydrogen and 1 mol of oxygen, 2 mol of water is formed. Hydrogen and water are in quantitative ratios of 2: 2. This means that their amount of matter will be the same.

n (H2) = n (H2O) = 0.6 mol.

2 mol H2 – 2 mol H2O,

0.6 mol H2 – x mol H2O,

X = (0.6 mol x 2 mol): 2 mol = 0.6 mol.

m = n M.

M (H2O) = 18 g / mol.

m = 18 g / mol x 0.6 mol = 10.8 g.

Answer: weight 10.8 g; the amount of substance is 0.6 mol.