Calculate the mass of water of crystallization in 280 g of Na2CO3 • 10H2O.

The molar mass of sodium carbonate (Na2CO3 • 10H2O) decahydrate is 286 g / mol. The molar mass of water is 18 g / mol. It follows that 286 grams of Na2CO3 • 10H2O contains 180 grams of water (18 * 10 = 180). From here we can find out how much water is contained in 280 g of Na2CO3 • 10H2O: 286 g (Na2CO3 • 10H2O) – 180 g (H2O)

280 g (Na2CO3 • 10H2O) – x g (H20)

x = (280 * 180) / 286 = 176.2 g H2O in 280 g Na2CO3 • 10H2O



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