Calculate the mass of water required to react with 0.23 g of sodium. What is the volume of the generated hydrogen?
| April 2, 2021 | education
Sodium, as an active metal, forms an alkali with water.
2Na + 2H2O = 2NaOH + H2.
If 23 g of sodium and 18 g of water enter into the reaction, then 0.18 g of water will react with 0.23 g of sodium.
If from 0.23 g of sodium – x l of hydrogen is released, then from 23 g of sodium – 22.4 l of hydrogen.
V (H2) = 0.23 g x 22.4 l / 23 g = 0.224 l.
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