Calculate the mass of water resulting from complete neutralization of a solution containing 19.6 g

Calculate the mass of water resulting from complete neutralization of a solution containing 19.6 g of sulfuric acid with sodium hydroxide solution.

Given:
m (H2SO4) = 19.6 g
To find:
m (H2O) =?
Decision:
1) We compose the equation of the chemical reaction, let the mass of water be x g.
H2SO4 + 2NaOH = Na2SO4 + 2H2O
2) Find the molecular weights of sulfuric acid and water.
M (H2SO4) = 2 + 32 + 64 = 98 g / mol
М (Н2О) = 2 + 16 = 18 g / mol, since water is 2, then 36 g / mol
3) 19.6 g: 98 g / mol = x g: 36 g / mol
x = (19.6 x 36): 98 = 7.2 g
Answer: m (H2O) = 7.2 g.