Calculate the mass of water that is formed during the combustion of hydrogen

Calculate the mass of water that is formed during the combustion of hydrogen with a volume of 1.12 liters. Calculate the volume of water vapor of this mass.

V (H2) = 1.12 l.
Let’s determine the volume of water that is obtained as a result of the reaction.
We write down the equation of reactions.
2H2 + O2 = 2H2O.
Find the volume of water.
1.12 l of hydrogen – x l of water
2 * 22.4 l / mol H2 – 2 * 22.4 l H2O
Find the unknown value of x.
X = 1.12 * 2 * 22.4: (2 * 22.4) = 1.12 liters of H2O.
Next, we find the mass of the resulting water. We write down the solution.
n = m / M.
n = V / Vm.
m / M = V / Vm.
m = M * V: Vm = 18 * 1.12: 22.4 = 0.9 g of water.
This means that as a result, water is formed with a mass of 0.9 grams.
Answer: m (H2O) = 0.9 g.



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