Calculate the mass of water that is produced by burning methane weighing 32 grams.

Let’s write the reaction equation: СН4 + 2О2 -> СО2 + 2Н2О Let us find n methane n = m / M n (CH4) = 32g / 16g / mol = 2 mol n (H2O) = 2n (CH4) = 4 mol The mass of Water is: m = M * nm (H2O) = 18g / mol * 4mol = 72g
Answer: 72 grams



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