Calculate the mass of water that will be released when 25 grams of methane interacts with oxygen.

1. Let’s compose the equation:
СН4 + 2О2 = СО2 + 2Н2О – carbon dioxide and water are released;
2. Molecular weights:
M (CH4) = 12 + 4 = 16 g / mol;
M (H2O) = 1 * 2 +16 = 18 g / mol;
3. Let’s calculate the number of moles of methane, if the mass is known:
Y (CH4) = m / M = 25/16 = 1.56 mol;
4. Let’s make the proportion:
1.56 mol (CH4) – X mol (H2O);
1 mol -2 mol from here, X mol (H2O) = 1.56 * 2/1 = 3.125 mol;
5. Find the mass of water by the formula:
m (H2O) = Y * M = 3.125 * 18 = 56.25 g.
Answer: the mass of water is 56.25 g.