Calculate the mass of zinc chloride forming the interaction of 40 grams of zinc oxide with hydrochloric acid.

1. The interaction of zinc oxide with hydrochloric acid proceeds according to the equation:

ZnO + 2HCl = ZnCl2 + H2O;

2.Calculate the chemical amount of zinc oxide:

n (ZnO) = m (ZnO): M (ZnO);

M (ZnO) = 65 + 16 = 81 g / mol;

n (ZnO) = 40: 81 = 0.4938 mol;

4.determine the amount of zinc chloride formed:

n (ZnCl2) = n (ZnO) = 0.4938 mol;

5.Calculate the mass of zinc chloride:

m (ZnCl2) = n (ZnCl2) * M (ZnCl2);

M (ZnCl2) = 65 + 35.5 * 2 = 136 g / mol;

m (ZnCl2) = 0.4938 * 136 = 67.16 g.

Answer: 67.16 g.