Calculate the mass of zinc formed when it is reduced by coal from oxide, weighing 810 g.

1. The reduction of zinc from its oxide with coal is described by the reaction equation:

ZnO + C = Zn + CO;

2. find the chemical amount of zinc oxide:

n (ZnO) = m (ZnO): M (ZnO);

M (ZnO) = 65 + 16 = 81 g / mol;

n (ZnO) = 810: 81 = 10 mol;

3.Set the amount of reduced zinc:

n (Zn) = n (ZnO) = 10 mol;

4.Calculate the mass of the zinc obtained:

m (Zn) = n (Zn) * M (Zn) = 10 * 65 = 650 g.

Answer: 650 g.