Calculate the mass of zinc hydroxide that reacts with 0.1 mol of sulfuric acid.

Given:

n (H2SO4) = 0.1 mol

m (Zn (OH) 2) -?

Decision:

Zn (OH) 2 + H2SO4 → ZnSO4 + 2H2O

1. Determine the molecular weights of zinc hydroxide and sulfuric acid:

M (Zn (OH) 2) = 65 + 16 * 2 + 1 * 2 = 99 g / mol;

M (H2SO4) = 1 * 2 + 32 + 16 * 4 = 98 g / mol.

2. Calculate the masses of zinc hydroxide and sulfuric acid according to the reaction equation:

m (Zn (OH) 2) = n * M = 1 mol * 99 g / mol = 99 g;

m (H2SO4) = n * M = 1 mol * 98 g / mol = 98 g.

3. Calculate the mass of sulfuric acid that has reacted:

m (H2SO4) = n * M = 0.1 mol * 98 g / mol = 9.8 g.

4. We calculate the mass of zinc hydroxide according to the proportion:

98 g —- 99 g

9.8 g —– x, where x is the mass of zinc hydroxide reacted.

x = (9.8 g * 99 g) / 98 g = 9.9 g.

Answer: 9.9 g of zinc hydroxide reacts with 0.1 mol of sulfuric acid.