Calculate the mass of zinc hydroxide that reacts with 0.1 mol of sulfuric acid.

Zn (OH) 2 + H2SO4 = ZnSO4 + 2H2O.

First, let’s convert the amount of sulfuric acid substance to mass:

m = n * Mr = 0.1 * 98 = 9.8 g.

Knowing that Mr (Zn (OH) 2) = 99 g, and Mr (H2SO4) = 98 g, we will compose the proportion and determine the mass of zinc hydroxide, which reacts with 9.8 g of sulfuric acid:

99 g – 98 g

x g – 9.8 g.

Hence x = 9.8 * 99/98 = 9.9 g is the mass of zinc hydroxide.