Calculate the mass of zinc hydroxide, which is formed by the interaction of 47 g of zinc sulfate with potassium hydroxide.

1. Let’s demonstrate the equation of the reaction of zinc sulfate with caustic potassium:

ZnSO4 + 2KOH = Zn (OH) 2 + K2SO4;

2. A portion of zinc sulfate contains the following chemical amount:

n (ZnSO4) = m (ZnSO4): M (ZnSO4);

M (ZnSO4) = 65 + 32 + 4 * 16 = 161 g / mol;

n (ZnSO4) = 47: 161 = 0.292 mol;

3. Determine the amount of hydroxide obtained:

n (Zn (OH) 2) = n (ZnSO4) = 0.292 mol;

4. Calculate the mass of zinc hydroxide:

m (Zn (OH) 2) = n (Zn (OH) 2) * M (Zn (OH) 2);

M (Zn (OH) 2) = 65 + 2 * 17 = 99 g / mol;

m (Zn (OH) 2) = 0.292 * 99 = 28.91 g.

Answer: 28.91 g.