Calculate the mass of zinc, which will result from the interaction of zinc chloride with aluminum weighing 108 g.

Reaction equation:
3ZnCl2 + 2Al = 3Zn + 2AlCl3
n (Al) = m \ M = 108 \ 27 = 4 mol
n (Zn) = 4 * 3 \ 2 = 6 mol
m (Zn) = nM = 6 * 65 = 390 g
Answer: m (Zn) = 390 g



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