Calculate the masses of calcium hydroxide and hydrochloric acid required to obtain calcium
Calculate the masses of calcium hydroxide and hydrochloric acid required to obtain calcium chloride weighing 222 g, according to the scheme: Ca (OH) 2 + HCl = CaCl2 + H2O
Given:
m (CaCl2) = 222 g
To find:
m (Ca (OH) 2) -?
m (HCl) -?
Decision:
Ca (OH) 2 + 2HCl = CaCl2 + 2H2O, – we solve the problem based on the composed reaction equation:
1) Find the amount of calcium chloride formed during the reaction:
n (CaCl2) = m: M = 222 g: 111 g / mol = 2 mol
2) Find the mass of calcium hydroxide through the first logical expression:
If 1 mol of Ca (OH) 2 gives 1 mol of CaCl2,
then x mol Ca (OH) 2 will give 2 mol CaCl2,
then x = 2 mol,
m (Ca (OH) 2) = n * M = 2 mol * 74 g / mol = 148 g.
3) Find the mass of hydrochloric acid through the second logical expression:
If 2 mol HCl gives 1 mol CaCl2,
then x mol HCl will give 2 mol CaCl2,
then x = 4 mol
m (HCl) = n * M = 4 mol * 36.5 g / mol = 146 g.
Answer: m (Ca (OH) 2) = 148 g; m (HCl) = 146 g.