Calculate the masses of the starting materials required to obtain 5.85 g of sodium chloride.

One of the ways to obtain sodium chloride has the following reaction equation:
2Na + 2HCl = 2NaCl + H2.
By the number of moles of reagents, the same amount is required as the salt obtained: 5.85 g: 58.5 g / mol = 0.1 mol.
Thus, you will need:
0.1 mol * 23 g / mol = 2.3 g sodium,
and 0.1 mol * 36.5 g / mol = 3.65 g HCl.



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