Calculate the maximum lift height of an arrow fired straight up from the bow. the initial speed of the boom is 40 m / s.

At the highest point, the speed of the arrow v will be 0. The acceleration of the arrow will be -9.8 m / s2 (acceleration of free fall, sign “-“, since the acceleration vector is directed in the opposite direction from the direction of motion)

v = v0 + at;

40 – 9.8 * t = 0;

t = 4.08 s;

The distance traveled by the boom (maximum height) will be:

S = v0 * t + a * t ^ 2/2 = 40 * 4.08 – 9.8 * 4.08 ^ 2/2 = 81.63 m.

Answer: S = 81.63 m.