Calculate the maximum possible perimeter of the parallelogram, the bisector of one of the corners of which divides

univerkov | January 13, 2021 | education

Calculate the maximum possible perimeter of the parallelogram, the bisector of one of the corners of which divides the side to which it is drawn into segments of 7 and 9 cm.

The largest perimeter of a rectangle is possible if the larger segment cut off by the bisector is located to the side from which the bisector emerges.
Then the bisector of the angle BAC cuts off the isosceles triangle ABN, in which AB = BH = 9 cm.
BC side length = (BH + CH) = 9 + 7 = 16 cm.
Let’s define the perimeter of the rectangle.
Ravsd = 2 * (AB + BC) = 2 * (9 + 16) = 50 cm.
Answer: The maximum perimeter of a rectangle is 50 cm.

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