Calculate the molarity of a 28% HNO3 solution (p = 1.167 g / cm3.).
| August 2, 2021 | education
The mass of nitric acid in 1 liter (1000 cm3) of a 28% solution with a density of ρ = 1, 167 g / cm3:
0.28 × 1000 × 1.167 = 326.8 g.
Molar mass of nitric acid:
M (НNO3) = 1 + 14 + 3 × 16 = 63 g / mol.
The mass of nitric acid 326.8 g corresponds to the amount of substance 326.8 / 63 = 5.19 mol.
Thus, the molarity of a 28% nitric acid solution is 5.19 mol / l = 5.19 M.
Answer: 5.19 mol / l.
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