Calculate the number of atoms in a vessel filled with gas weighing 50 g, if this gas is helium.

Problem data: m (mass of helium filling the vessel) = 50 g.

Reference data: M (molar mass of helium) ≈ 4 g / mol; Na (Avogadro’s number) = 6.02 * 10 ^ 23 mol-1.

The number of helium atoms in a vessel can be expressed from the equality: N / Na = m / M, whence N = Na * m / M.

Let’s perform the calculation: N = 6.02 * 10 ^ 23 * 50/4 = 75.25 * 10 ^ 23 atoms.

Answer: A vessel filled with helium contains 75.25 * 10 ^ 23 atoms.



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