Calculate the percentage of Fe2 O3?

According to the condition, we were given the task to calculate the percentage of bivalent iron oxide. Chemical formula Fe2O3.

ω = m1 / m х 100%

Find the molar mass of iron oxide.

Mr (Fe2O3) = 56 * 2 + 16 * 3 = 160
ω (Fe) = 56 * 2/160 = 0.7 or 70%
ω (O) = 16 * 3/160 = 0.3 or 30%.

Answer: bivalent iron oxide contains 70% iron and 30% oxygen.



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