Calculate the perimeter and area of a rectangle whose width is 8 cm and the length is 23 times greater.

Let’s find the length of the given rectangle.

According to the condition of the problem, the width of this rectangle is 8 cm, and its length is 23 meters less, therefore, the width of this rectangle is:

23 * 8 = 184 cm.

Find the perimeter p of a given rectangle as the doubled sum of the length and width of this rectangle:

p = 2 * (184 + 8) = 2 * 192 = 384 cm.

Find the area S of a given rectangle as the product of the length and width of a given rectangle:

S = 184 * 8 = 1472 cm².

Answer: the perimeter of this rectangle is 384 cm, the area of this rectangle is 1472 cm².