Calculate the perimeter of a rectangle, the length of which is 1200 mm, and the width is 2 times less.

1. The problem statement says about a rectangle.
It is known that its length is 1200 mm.
The width is not explicitly set, but the problem says that it is 2 times less than its length.
Let’s calculate the width.
1200/2 = 600 mm.
2. The perimeter of a rectangle is twice the sum of its length and width.
Let’s find the perimeter according to the given parameters and write down its value in decimeters.
P = 2 * (1200 + 600) = 2 * 1800 = 3600 mm = 36 dm.
3. The area is determined by the product of length and width.
S = 1200 * 600 = 720,000 mm2 = 72 dm2.
Answer: The perimeter of the rectangle is 36 dm2, the area is 72 dm2.