Calculate the perimeter of the triangle by the coordinates of its vertices A (-2; 1), B (2, -2), C (8; 6).
| May 29, 2021 | education
Determine the lengths of the sides of the triangle by the coordinates of its vertices.
AB = √ (X2 – X1) ^ 2 + (Y2 – Y2) ^ 2 = √ ((2 – (-2)) ^ 2 + (-2 – 1) ^ 2) = √ (16 + 9) = √ 25 = 5 cm.
AC = √ ((8 – (-2)) ^ 2 + (6 – 1) ^ 2) = √ (100 + 25) = √125 = 5 * √10 cm.
ВС = √ ((8 – 2) ^ 2 + (6 – (-2)) ^ 2) = √ (36 + 64) = √100 = 10 cm.
Determine the perimeter of the triangle.
Ravs = AB + AC + BC = 5 + 5 * √10 + 10 = 15 + 5 * √10 cm.
Answer: The perimeter of the triangle is 15 + 5 * √10 cm.
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