Calculate the perimeter of the triangle, one side of which is 56 millimeters and the other two are 62 millimeters.

The perimeter of any triangle is equal to the sum of the lengths of all three sides of this triangle.
According to the condition of the problem, in this isosceles triangle, the lengths of two sides are 62 millimeters, and the length of the third side is 56 millimeters, therefore, the perimeter P of this triangle is:
62 + 62 + 56 = 124 + 56 = 180 mm.
Answer: The perimeter of this triangle is 180 millimeters.



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