Calculate the perimeter of the walls if the length of the room is 4 m, width is 3 m. The height of the ceiling is 3 m.
The room has four walls. Opposite walls are equal. Therefore, we get two walls with sides 4 m long, which is equal to the width of the room and the width of 3 m, which is equal to the height of the room, and two more walls with sides are 3 m long, which is equal to the length of the room and the width of 3 m, which is equal to the height of the room. The perimeter of the rectangle is equal to the sum of all its sides, and since the opposite sides of the rectangle are equal, we can write down that the perimeter is: P = a + b. Find the perimeters of the walls. The perimeter of the first two walls is: P = 2 * 4 m + 2 * 3 m = 8 m + 6 m = 14 m.The perimeter of the second two sides is: P = 2 * 3 m + 2 * 3 m = 6 m + 6 m = 1 2m.
Answer: two walls with a perimeter of 14 m and two walls with a perimeter of 12 m.