Calculate the period of natural oscillations in an oscillatory circuit with a capacitor capacity of 2 μF

Calculate the period of natural oscillations in an oscillatory circuit with a capacitor capacity of 2 μF and a coil inductance of 0.5 mH

Data: C – capacitance of the circuit capacitor (C = 2 * 10-6 F (2 μF)); L is the inductance of the loop coil (L = 5 * 10-4 H (0.5 mH)).

To calculate the required period of natural oscillations, consider the Thomson formula: Tx = 2 * Π * √ (L * C).

Let’s perform the calculation: Tx = 2 * Π * √ (L * C) = 2 * 3.14 * √ (5 * 10-4 * 2 * 10-6) ≈ 2 * 10-4 s or 0.2 ms.

Answer: The oscillation period, according to the calculation, should be 0.2 ms.