Calculate the power of the hoist motor, with the help of which their 60 m deep shaft lifts 2 tons of ore in 40 s.

These tasks: h (the depth of the mine from which the ore is raised) = 60 m; m (mass of ore raised) = 2 t (2000 kg); t (duration of the hoist motor) = 40 s.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

We calculate the required power of the hoist motor by the formula: N = A / t = F * S / t = m * g * h / t.

Calculation: N = 2000 * 10 * 60/40 = 30000 W or 30 kW.

Answer: The lift motor has a power of 30 kW.




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