Calculate the pressure and force of pressure of kerosene at the bottom of a tank with an area of 50 dm2

Calculate the pressure and force of pressure of kerosene at the bottom of a tank with an area of 50 dm2, if the height of the column of kerosene in the tank is 40 cm.

Task data: S (area of the bottom of the tank with kerosene) = 50 dm2 (50 * 10 ^ -2 m2 = 0.5 m2); h (height of the column of kerosene in the tank) = 40 cm (0.4 m).

Reference data: g (acceleration due to gravity) ≈ 10 m / s2; ρк (kerosene density) = 800 kg / m3.

1) Calculate the pressure of kerosene: P = ρк * g * h = 800 * 10 * 0.4 = 3200 Pa (3.2 kPa).

2) Determine the force of pressure of kerosene to the bottom: F = P * S = 3200 * 0.5 = 1600 N (1.6 kN).

Answer: Kerosene creates a pressure of 3.2 kPa at the bottom of the tank, the pressure force of kerosene is 1.6 kN.