Calculate the proportion of nitrogen in a gas mixture that contains 32 liters of nitrogen, 48 grams of carbon monoxide

Calculate the proportion of nitrogen in a gas mixture that contains 32 liters of nitrogen, 48 grams of carbon monoxide (4 valencies), 36 grams of helium and 15 liters of hydrogen

1.Let’s find the mass of nitrogen by the formula m = n M.

We find the amount of substance by the formula: n = V: Vn

n = 32 L: 22.4 L / mol = 1.43 g

M (N2) = 14 × 2 = 28 g / mol.

m = 1.43 g × 28 g / mol = 40 g.

2.Let’s find the mass of hydrogen.

n = 15 L: 22.4 L / mol = 0.67 mol.

M (H2) = 2 g / mol.

m (H2) = 2 g / mol × 0.67 mol = 1.34 g.

3. Find the mass of the entire mixture.

m (mixture) = 40 g + 1.34 + 48 g + 36 g = 125.34 g.

4. Let’s find the mass fraction of nitrogen in the mixture.

W = (40g: 125.34g) × 100% = 31.91%.