Calculate the required mass of nitric acid for interaction with 12 liters of ammonia.

1. Let’s compose the reaction equation:

HNO3 + NH3 = NH4NO3

According to the equation, all substances are taken in an amount of 1 mol:
the volume of ammonia is calculated by the formula: V (NH3) = Vm * n = 22.4 l / mol * 1 mol = 22.4 l;
we find the mass of nitric acid by the formula: m (HNO3) = n * M = 1 * (1 + 14 + 16 * 3) = 63 g.
2. Let’s calculate the mass of nitric acid, making up the proportion:

12 l NH3 – x g HNO3

22.4 l NH3 – 63 g HNO3

Hence, x = 12 * 63 / 22.4 = 33.75 g.