Calculate the specific binding energy of the helium 4 He atom.

The binding energy of the nucleus is equal to the minimum energy that must be applied for the complete splitting of the nucleus into particles.
E = Δm * c², where Δm is the difference between the mass of the nucleus and its components.
Δm = Z * mp + N * mn-Mя, where Z is the number of protons in the nucleus, mp is the proton mass mp = 1.00728 amu, N is the number of neutrons in the nucleus, mn is the neutron mass mn = 1 , 00866, My is the mass of the nucleus.
With this in mind, the binding energy:
E = Δm * c² = (Z * mp + N * mn-My) * c².
In the helium nucleus there are 4 – 2 protons, 2 neutrons, My = 4.003 amu.
Δm = Z * mp + N * mn-My = 2 * 1.00728 + 2 * 1.00866-4.003 = 0.02888 amu.
Let’s translate into kilograms:
Δm = 0.02888 * 1.6606 * 10 ^ -27 = 4.7958 * 10 ^ -29 kg.
E = Δm * c² = 1.4198 * 10 ^ -29 * (3 * 10 ^ 8) ² = 4.3162 * 10 ^ -12 J.
Specific binding energy is the binding energy per 1 nucleon, we have 4 of them:
Esp = E / A = 4.3162 * 10 ^ -12 / 4 = 1.079 * 10 ^ -12 J.
Answer: Eud = 1.079 * 10 ^ -12 J.