Calculate the stiffness of the spring which, under the action of a force of 4 Newtons, lengthened by 2 cm.

univerkov | November 28, 2020 | education

Spring force: F = k * x, where k is the coefficient of spring stiffness and x is the elongation.
By condition, the elongation is 2 cm. We translate into SI. 2 cm = 0.02 m.
The force is 4 Newtons.
Since F = k * x, it means to find k = F / x.
k = 4 N / 0.02 m = 200 N / m.
Answer: k = 200 N / m.

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