Calculate the strength of two different electric fields acting on the charge q = 0.004C

Calculate the strength of two different electric fields acting on the charge q = 0.004C with a force F1 = 0.08 H and F2 = 0.012H.

These tasks: q (charge on which electric fields act) = 0.004 C; F1 (acting force from the first field) = 0.08 N; F2 (acting force from the second field) = 0.012 N.

1) The strength of the first electric field: E1 = F1 / q = 0.08 / 0.004 = 20 V / m.

2) The strength of the second electric field: E2 = F2 / q = 0.012 / 0.004 = 3 V / m.

Answer: The strengths of two different electric fields are, respectively, 20 V / m and 3 V / m.