Calculate the tangent 45 + cosine 30 – minus 60. In a right-angled triangle ABC, legs AB and AC are 3 and 4 cm

Calculate the tangent 45 + cosine 30 – minus 60. In a right-angled triangle ABC, legs AB and AC are 3 and 4 cm, respectively. Find the sine B, cosine B and tangent B. In a right-angled triangle, the legs are 4 and 4 roots of 3 cm. Find the corners of the triangle …

1) Since tg45, cos30 and sin60 are tabular values, we know them
tg45 + cos30-sin60 = 1 + √3 / 2 – √3 / 2 = 1
2) In a right-angled triangle ABC, where the legs AB and AC are equal to 3 and 4 cm, respectively:
Sine is the ratio of the opposite leg to the hypotenuse, the cosine is the adjacent leg to the hypotenuse, and the tangent is the ratio of the opposite leg to the adjacent leg.
By the Pythagorean theorem BC ^ 2 = AB ^ 2 + AC ^ 2
BC ^ 2 = 9 + 16 = 25
BC = 5 cm
sinB = 4/5 = 0.8
cosB = 3/5 = 0.6
tgB = 4/3
3) In a right-angled triangle, the legs are 4 and 4√3 cm:
A – right angle, AB = 4 cm, AC = 4√3 cm
BC – hypotenuse
By the Pythagorean theorem BC ^ 2 = AB ^ 2 + AC ^ 2
BC ^ 2 = 16 * 3 + 16 = 64
BC = 8 cm
The leg, lying opposite an angle of 30 degrees, is equal to half of the hypotenuse
The AB leg is equal to half of the BC hypotenuse, so the angle C = 30 degrees
Angle B = 90-30 = 60 degrees.