Calculate the V (H2) that needs to be passed through ethylene to form ethane m = 15.6 g.

Let’s carry out the solution, make up the equation:
C2H4 + H2 = C2H6 – hydrogenation reaction, hydrogen is added due to the breaking of the double bond, ethane was formed;
M (H2) = 2 g / mol;
M (C2H6) = 30 g / mol.
Let’s calculate the number of moles of ethane, if its mass is known:
Y (C2H6) = m / M = 15.6 / 30 = 0.52 mol.
According to the equation, we compose the proportion:
X mol (H2) – 0.52 mol (C2H6);
1 mol – 1 mol from here, Y (H2) = 0.52 mol.
Find the volume of hydrogen:
V (H2) = 0.52 * 22.4 = 11.65 liters.
Answer: the volume of hydrogen is 11.65 liters.