Calculate the voltage at the terminals of the ammeter, the current in which is 6.2 A

Calculate the voltage at the terminals of the ammeter, the current in which is 6.2 A, if the resistance of the ammeter is 1.2 mΩ.

I = 6.2 A.

R = 1.2 mΩ = 0.0012 Ω.

U -?

According to Ohm’s law for a section of the circuit, the current I in the ammeter is directly proportional to the voltage U at the terminals of the ammeter and is inversely proportional to its resistance R: I = U / R.

Let us express the voltage at the terminals of the ammeter: U = I * R.

U = 6.2 A * 0.0012 Ohm = 0.00744 V = 7.44 mV.

Answer: the voltage at the ammeter terminals is U = 0.00744 V = 7.44 mV.