Calculate the voltage between the plates of the capacitor, if the capacitance of the capacitor is 0.5 μF.

Calculate the voltage between the plates of the capacitor, if the capacitance of the capacitor is 0.5 μF. 200V, and the charge a of one plate is 2 nC.

Let’s translate all the values from given to the SI system:
q = 2 nC = 2 * 10 ^ -9 C.
C = 0.5 μF = 0.5 * 10 ^ -6 F.
The electrical capacity of a system of two conductors is a physical quantity defined as the ratio of the charge q of one of the conductors to the potential difference Δφ between them:
С = q / U, we express the voltage from this expression:
U = q / C = 2 * 10 ^ -9 / 0.5 * 10 ^ -6 = 0.004 V.
Answer: 0.004 V or 4 mV.