Calculate the volume, amount of substance and mass of gas obtained by the interaction of 12 g
| December 10, 2020 | education
Calculate the volume, amount of substance and mass of gas obtained by the interaction of 12 g of magnesium with water taken in excess.
Mg + 2H2O = Mg (OH) 2 + H2 n (Mg) = 12/24 = 0.5 mol, therefore, n (H2) is also equal to 0.5 volume of 1 liter of gas when n is equal to 22.4 liters => v (h2) = 11.2 liters m (H2) = 2 * 0.5 g
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